薪酬核算人员重复，什么原因？
【关键字】：员工管理、薪酬核算、人员重复
【适用版本】：通用
【解决方案】：
选取一个重复的员工，按下面步骤操作。
1、select fid from t_bd_person where fnumber ='重复的人员编码'
2、SELECT "T0"."FID" "ID", "T0"."FPERSONID" "T1.ID",
"T1"."FNAME_L2" "T1.NAME", "T1"."FNAME_L1" "T1.NAME_L1",
"T1"."FNAME_L2" "T1.NAME_L2", "T1"."FNAME_L3" "T1.NAME_L3",
"T0"."FADMINORGID" "T2.ID", "T2"."FNAME_L2" "T2.NAME",
"T2"."FNAME_L1" "T2.NAME_L1", "T2"."FNAME_L2" "T2.NAME_L2",
"T2"."FNAME_L3" "T2.NAME_L3", "T0"."FPOSITIONID" "T3.ID",
"T3"."FNAME_L2" "T3.NAME", "T3"."FNAME_L1" "T3.NAME_L1",
"T3"."FNAME_L2" "T3.NAME_L2", "T3"."FNAME_L3" "T3.NAME_L3"
from "T_HR_EMPORGRELATION" "t0"
left OUTER JOIN "T_BD_PERSONHIS" "t1"
on (("T0"."FPERSONID" = "T1"."FHISTORYRELATEID"
and ("T1"."FEFFDT" <= "T0"."FEFFDT"))
and ("T1"."FLEFFDT" >= "T0"."FEFFDT"))
left OUTER JOIN "T_ORG_ADMINHIS" "t2"
on (("T0"."FADMINORGID" = "T2"."FHISTORYRELATEID"
and ("T2"."FEFFDT" <= "T0"."FEFFDT"))
and ("T2"."FLEFFDT" >= "T0"."FEFFDT"))
left OUTER JOIN "T_ORG_POSITIONHIS" "t3"
on (("T0"."FPOSITIONID" = "T3"."FHISTORYRELATEID"
and ("T3"."FEFFDT" <= "T0"."FEFFDT"))
and ("T3"."FLEFFDT" >= "T0"."FEFFDT"))
where (((("T0"."FASSIGNTYPE" = 1
and "T1"."FHISTORYRELATEID" = '上面语句返回的fid')
and "T0"."FISINNER" = 1)
and ("T0"."FEFFDT" <= {ts '2016-06-28'}))
and ("T0"."FLEFFDT" >= {ts '2016-06-28'}))
其中的日期，请改为当前日期，返回的记录是否存在两条或多条,把反馈结果导出到excel表里,可以看出是组织或则岗位存在重复数据，然后把重复的岗位历史或则组织历史删除。
下面语句可以查询是否存在重复组织，如果重复，需要把重复记录删除。
select fhistoryrelateid ,count(*) from t_org_adminhis group by
feffdt,fleffdt,fhistoryrelateid having
count(*)>1
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